Andrés Clemente Vázquez (22-11-1844 - 21-02-1901) Cuban-Mexican composer
Andrés Clemente Vázquez published in 1898 "
En el ocaso", a compilation of his articles (
source). He also published in 1874 "
Análisis del juego de ajedrez".
He was the first chess club president of Mexico and composed direct mates.
Vázquez, Andrés Clemente
Enigmas Problemas, 1890
Show Solution1.Sd4-e6 !
(2.Bf3-h5+ Kf7-f6 3.Re8-f8# or 2.Bf3-e4 [3.Re8-f8#] 2...Kf7xe8 3.Be4-g6#)
1...Kf7-f6 2.Bf3-e4 ~ 3.Re8-f8#
1...Kf7-g6 2.Bf3-e4+ Kg6-h6/h5 3.Re8-h8# or 2...Kg6-f6/f7 3.Re8-f8#
Владимир Ильич Трояновский (22-11-1924) Belarusian composer (Vladimir Ilich Troyanovsky)
Vladimir Troyanovsky composes direct mates.
Трояновский, Владимир Ильич
Revista de Şah, 1960
2
nd Prize
Show Solution1.Rg5-h5 ! (2.d2-d4+ Sb5xd4, Ke5xe4 3.Qb4xd4, Qb4-b1#)
1...Rf3xf5 2.Bh6-f4+ Ke5-e6 3.Qb4-c4#
1...Qc8xf5 2.Sb6-d7+ Ke5-e6 3.Sh7xf8#
1...Rf8xf5 2.Bh6-g7+ Ke5-e6 3.Sh7-g5#
Three variations with trial avoidance and pin mates.
Secondary variations:
1...c6-c5 2.Qb4xc5+ Ke5xe4 3.Qc5-d5#
1...Rf3xe3 2.Qb4-c5+ Ke5xe4 3.Qc5xe3#
Teppo Mänttä (22-11-1954) Finnish composer
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Teppo Mänttä looking at Kari Valtonen who is showing a problem to Pauli Perkonoja at Riccione WCCC, 1985
[© Hannu Harkola] |
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Teppo Mänttä
[© Hannu Harkola] |
Teppo Mänttä is a direct mate, helpmate and fairy composer who is mostly devoted to fairy chess (T.R.Dawson is his guru). He won for instance the
Wenigsteinerjahrespreis 2009 with this problem. One of his favourites is his 2
nd place in the WenigsteinerJahresPreis 2016 which you can see
here.
Below is another problem, composed in an era without computer check:
Mänttä, Teppo
TT, Springaren, 1986
1
st Prize
Show Solutiona) 1.Gf5-d3 e2xd3 2.Gd7-f5 d3xe4 3.Ke8-d7 e4xf5 4.Kd7-c6 f5xe6 5.Kc6-b5 e6xf7 6.Gd5-g8 f7xg8=Q 7.Kb5-a4 Qg8-c4#
b) 1.Gd5-f3 e2xf3 2.Rd7-d5 f3xe4 3.Rf7-d7 e4xd5 4.Ke8-f7 d5xe6+ 5.Kf7-g6 e6xd7 6.Gf5-c8 d7xc8=Q 7.Kg6-h5 Qc8-f5#
Echo mates, two Excelsiors by the same pawn.
Григорий Сергеевич Атаянц (22-11-1954) Russian composer and FIDE Master (Grigory Sergeyevich Atayants)
Grigory Atayants has been composing direct mates since 1970, with some breaks. He is also a writer with 2 books published.
Атаянц, Григорий Сергеевич
7
th ECSC, Łowicz, 2011 (32)
2
nd Prize
Show Solution1. Qf2! (2. Rd4+ cxd4 3. Qxd4#)
1... Sc6 2. Se5+! (2.Qxc5+?) 2... Sxe5 3. Qf4# or 2... Bxe5 3. Qxc5#
1... Se6 2. Qxc5+! (Se5+?) 2... Bxc5 3. Se5# or 2... Sxc5 3. Rd4#
The difficult Keller paradox: White moves on the square that has just been overguarded by Black.
Secondary variations:
1... e5 2. Qe2 b3, c2 3. Rd4, Qxc2#
1... Qb6 2. Qa2+ b3 3. Qxb3#
Olivier Schmitt (22-11-1966) French composer and International Master
Olivier Schmitt was a good chess player as a junior (4th in French national championship) and started composing chess problems in 1983. He stopped however in the 1990s and resumed this activity after an 11-year break. He composes moremovers, especially very long problems with foreplan and tries and pendulum manoeuvres.
He was the moremover editor of the French magazine
diagrammes.
More information about him can be found
on his website. On this same page, you can find a PDF file with a complete collection of his problems, commented in French (
current link). He also presents his Top 100
on this page.
Here are two of his best works:
Schmitt, Olivier
The Problemist 1994
1 st Prize
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Show SolutionTry: 1.Bd4 ? (2.Be3#) Re7 !
The circuits of the wSs in the foreplan will force the black Rook to capture wPa6 and will prevent this refutation by Re7.
1.Sc5 ! (2.Sb3#)
1...Kc1 2. Sb3+ Kb2 3.Sd4 (4.Sd3#)
3...Kc1 4.Sd3+ Kd2 5.Sxb4 (5.Sb3#)
5...Kc1 6.Sd3+ Kd2 7.Se1 Kc1 8.Bd6 ! (9.Bxa3+)
8...Rxa6
The rook has been attracted away from e7. Now the second wS must be brought back to its initial square:
9.Sb3+ Kb2 10.Sc5 Kc1 11.Scd3+ Kd2
and finally 12.Bc5 ~ 13.Be3#
Secondary variations:
7...Rb7 8.axb7 Kc1 9.b8=Q ~ 10.Qb2+ !
8...c5 9.Bxc5 Rxa6 10.Sb3+ Kb2 11.Be3 & 12.Bc1#
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Schmitt, Olivier
harmonie 2015
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Show SolutionTries:
1.Ba6+? Rxa6 2.Rd8+ Kb7 3.Rb8+ Ka7 4.Sb5+ cxb5
1.Sd5? (2.Sb6 or 2.Se7#) cxd5? 2.Ba6+ etc but 1...exd5 !
This is why White must first clear diagonal c8-h3 for wBf1.
1.Rc2 ! (2.Sxc6 Sxc6 3.Rxc6#)
1...Bxc2 2.Rc7+ Kb8 3.Rxf7+ Kc8 4.Rc7+ Kb8 5.Re7+ Kc8 6.Sd5 ! (7.Sb6#)
6...cxd5 (now 6..exd5 7.Bh3+ mates in 2)
7.Rc7+ Kb8 8.Rd7+ Kc8 9.Ba6+ ! Rxa6 10.Rd8+ Kb7 11.Rb8+ Ka7 12.Sb5# model mate
This logical problem comprises two foreplans including 3 sacrifices and a model mate.
In the first foreplan, bBf5 is attracted away from line c8-h3 and then bPf7 is annihilated (in order to avoid f7-f5) and finally the wR is temporarily placed on e7 that is not guarded by Black.
Other variations:
1...Be4 2.Sxc6 ! Bxc6
[or 2..Sxc6 3.Bb5 (threatening 4.Bxc6) e5 (Ra7) 4.Sxg6 (Rxa7) mates in #2]
3.Bb5 ! (same threat) Ra7 (Sc4) 4.Rxc6+ (Rxc4) Sxc6 (Ra7) 5.Rxa7 (Rxc6+) mates in 2
1.. e5 2.Rxc6+ Sxc6 3.Rc7+ Kb8 4.Sxc6#
6..b1=Q 7.Rc7+ Kb8 8.Rd7+ Kc8 9.Se7#
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