Sigmund Weidisch (01-02-1887 - 1955) German composer
Show Solution
Tuesday, January 31, 2012
Monday, January 30, 2012
January 31st
Søren Anton Sørensen (31-01-1840 - 11-02-1896) Danish composer
According to Martin Møller, whose Skakjournal was quoted here in 2009:
Martin Møller then narrates a little anecdote which you may read on Rick Kennedy's Jerome Gambit blog. Anyway, S.A.S. was a talented chess player, whose games you may browse through on ChessGames.com.
He also wrote with A. Arnell an anthology of Nordic problems: "Nordiske Skakproblemer" (1879) that can be read on Anders Thulin website.
Sørensen won a tourney organised by the BCF in 1873. One of the problems of the set was the following:
Show Solution
Søren_Anton_Sørensen [Wikipedia.da] |
According to Martin Møller, whose Skakjournal was quoted here in 2009:
"Søren Anton Sørensen was taught chess at the age 11 (1851) by H.Møller, when he was a regular visitor at Sulsted præste-gård (vacarage) - (H.Møller was former chairman in the first Copenhagen chess club/Københavns skak forening 1844-1846)."
He also wrote with A. Arnell an anthology of Nordic problems: "Nordiske Skakproblemer" (1879) that can be read on Anders Thulin website.
Sørensen won a tourney organised by the BCF in 1873. One of the problems of the set was the following:
Show Solution
1.Rf3! (2.Qf6+ Kxe4 3.Re3#)
1...Sxf3 2.Sc6+ Sxc6 3.Qd5+ Kf6 4.Qe6# or 2...Kxe4 3.Qd5+ Sxd5 4.Bc2#Model mates.
1...Bxf3 2.Sc6+ Sxc6 3.Qd5+ Kf6 4.Qe6# or 2...Kxe4 3.Qe8+ Re7/Kd3/Kf5 4.Qg6/Qe3/Qe6#
1...Re7 2.Rf5+ Kxe4 3.Qxe7+ Kd3,Kxd4 4.Qe3#
1...Rf7/Sxg2 2.Sc6+ Kxe4 3.Qd4+ Kxf3 4.Bd1#
1...Sec2 2.Qf6+ Kxe4 3.Se6 (4.Sc5,Qf5#)
1...Rg6 2.Sf5 (3.Qd4#) Rd6 3.Qe7+ Re6 4.Qxe6# or 2...Sc6 3.Qd5+ Kf6 4.Qe6# or 2...Kxe4 3.Qd4+ Kxf3 4.Bd1# (2...Sd5 3.Qxd5+ Kf6 4.e5,Qd4,Qe6# or 2...Se~/Sbc2/Bb6 3.Qe8+,Qe7+/Qe8+,Qd5+,Qe7+/Qe8+,Qe7+)
Sunday, January 29, 2012
January 30th
Samuel Loyd (30-01-1841 - 10-04-1911) American composer
Does Sam Loyd need any introduction? Please refer to the Wikipedia webpage which also quotes the famous Excelsior problem that is reproduced below.
Show Solution
1.b4 ! (threatens 2.Rf5 [3.Rf1#] Rc5 3.bxc5 ~ 4.Rf1#)
1...Rc5 2.bxc5 (3.Rb1#)
2....a2 3.c6 (4.Rf5 ~ 5.Rf1#)
4...Bc7 4.cxb7 ~ 5.bxa8=B/Q#
Excelsior.
Samuel Loyd [Wikipedia] |
Does Sam Loyd need any introduction? Please refer to the Wikipedia webpage which also quotes the famous Excelsior problem that is reproduced below.
Show Solution
1.b4 ! (threatens 2.Rf5 [3.Rf1#] Rc5 3.bxc5 ~ 4.Rf1#)
1...Rc5 2.bxc5 (3.Rb1#)
2....a2 3.c6 (4.Rf5 ~ 5.Rf1#)
4...Bc7 4.cxb7 ~ 5.bxa8=B/Q#
Excelsior.
Saturday, January 28, 2012
January 29th
Miroslav Bílý (29-01-1945) Czech composer
Miroslav Bílý composes helpmates presenting (chameleon) echo mates and he even wrote a book about them.
Show Solution
Miroslav Bílý composes helpmates presenting (chameleon) echo mates and he even wrote a book about them.
Show Solution
a) 1...Bd7 2.Rb7 Bh3 3.Re7 g4 4.Ke6 g5#
b) 1...Bh2 2.Re6 g3 3.Ke5 Bc6 4.Sf6 g4#
Chameleon echo mates.
b) 1...Bh2 2.Re6 g3 3.Ke5 Bc6 4.Sf6 g4#
Chameleon echo mates.
Friday, January 27, 2012
January 28th
John Poole (28-01-1882 - 1956) British composer
Show Solution
Show Solution
1.Rd1 ! ZZ
1...f5 2.Rh6+ f6 3.Rxf6+ Kxf6 4.Rd6#
1...e4 2.Rd5 f5 3.Rd6+ Ke5 4.Rd5#
The second variation presents a Turton doubling.
1...f5 2.Rh6+ f6 3.Rxf6+ Kxf6 4.Rd6#
1...e4 2.Rd5 f5 3.Rd6+ Ke5 4.Rd5#
The second variation presents a Turton doubling.
Thursday, January 26, 2012
January 27th
Charles Lutwidge Dodgson, alias Lewis Carroll (27-01-1832 - 14-01-1898)
British mathematician, writer, chessplayer and composer
Many things could be said about Lewis Carroll, but here we focus on chess problems. Lewis Carroll's chess problem published in "Through the Looking Glass" is the following:
1.Sg3+! Kd3(d4) 2.Qc3# (short mate)
1....Ke5 2.Qc5+ Ke6 3.Qd6#
In fact, the stipulation is wrong. As the source says it should be "White Pawn to play and win in eleven moves." And as the printed solution indicates, the rules of chess are not very strictly adhered to...
Show the Solution intended by Lewis Caroll
British mathematician, writer, chessplayer and composer
Lewis Carroll [Wikipedia] |
Many things could be said about Lewis Carroll, but here we focus on chess problems. Lewis Carroll's chess problem published in "Through the Looking Glass" is the following:
1.Sg3+! Kd3(d4) 2.Qc3# (short mate)
1....Ke5 2.Qc5+ Ke6 3.Qd6#
In fact, the stipulation is wrong. As the source says it should be "White Pawn to play and win in eleven moves." And as the printed solution indicates, the rules of chess are not very strictly adhered to...
Show the Solution intended by Lewis Caroll
1. Alice meets R.Q. R.Q. to K.R's 4th
2. Alice through Q's 3d (by railway) to Q's 4th
Tweedledum and Tweedledee W.Q. to Q.B's 4th (after shawl)
3 Alice meets W.Q. (with shawl) W.Q. to Q. B's 5th (becomes sheep)
4 Alice to Q's 5th (shop, river, shop) W.Q. to K. B's 8th (leaves egg on shelf)
5 Alice to Q's 6th (Humpty Dumpty) W.Q. to Q.B's 8th (flying from R. Kt.)
6 Alice to Q's 7th (forest) W. Kt. takes R. Kt. R. Kt. to K's 2nd (ch.)
7 W. Kt. takes R. Kt. W. Kt. to K. B's 5th
8 Alice to Q's 8th (coronation) R. Q. to K's sq. (examination)
9 Alice becomes Queen Queens castle
10 Alice castles (feast) W.Q. to Q. R's 6th (soup)
11 Alice takes R. Q. & wins
The solution in animated gif can be seen on this website:
Some explanations about this strange series of moves can be found here and Christophe Leroy proposes a decryption of the game in English and in French.
2. Alice through Q's 3d (by railway) to Q's 4th
Tweedledum and Tweedledee W.Q. to Q.B's 4th (after shawl)
3 Alice meets W.Q. (with shawl) W.Q. to Q. B's 5th (becomes sheep)
4 Alice to Q's 5th (shop, river, shop) W.Q. to K. B's 8th (leaves egg on shelf)
5 Alice to Q's 6th (Humpty Dumpty) W.Q. to Q.B's 8th (flying from R. Kt.)
6 Alice to Q's 7th (forest) W. Kt. takes R. Kt. R. Kt. to K's 2nd (ch.)
7 W. Kt. takes R. Kt. W. Kt. to K. B's 5th
8 Alice to Q's 8th (coronation) R. Q. to K's sq. (examination)
9 Alice becomes Queen Queens castle
10 Alice castles (feast) W.Q. to Q. R's 6th (soup)
11 Alice takes R. Q. & wins
The solution in animated gif can be seen on this website:
Some explanations about this strange series of moves can be found here and Christophe Leroy proposes a decryption of the game in English and in French.
Wednesday, January 25, 2012
January 26th
Сергій Миколайович Ткаченко (26-01-1963) Ukrainian composer and International Master (Sergey Mikolayovich Tkachenko)
Not to be confounded with Сергій Іванович Ткаченко.
Show Solution
Not to be confounded with Сергій Іванович Ткаченко.
Сережа Ткаченко |
Show Solution
1. Rc7!
{1. Rc1? g1Q! 2. Bc3+ Kg8! 3. R:g1 =}
1... g1=Q 2. Bc3+ Se5! 3. Bxe5+ Kg8 4. Sg3!
{4. Rg7+? Qxg7 5. Bxg7 Bxe4 =}
4... Bg6+ 5. Ke7 Bxe4! 6. Rc8+!
{6. Sxe4? Qg5+! 7. Sxg5 =}
6... Kh7 7. Rh8+ Kg6 8. Rg8+ Kh7 9. Rg7+
{1. Rc1? g1Q! 2. Bc3+ Kg8! 3. R:g1 =}
1... g1=Q 2. Bc3+ Se5! 3. Bxe5+ Kg8 4. Sg3!
{4. Rg7+? Qxg7 5. Bxg7 Bxe4 =}
4... Bg6+ 5. Ke7 Bxe4! 6. Rc8+!
{6. Sxe4? Qg5+! 7. Sxg5 =}
6... Kh7 7. Rh8+ Kg6 8. Rg8+ Kh7 9. Rg7+
9... Kh6 10. Sf5+ Kh5 11. Rxg1 +-A spectacular study with multiple finesses.
9... Kh8 10. Kf8! Qc5+ 11. Re7+ Qxe5 12. Rxe5 +-
Tuesday, January 24, 2012
January 25th
Hans Theo Kuner (25-01-1929) German composer
Of Hans Theo Kuner (or Theo Kuner) many problems could be quoted. May the reader be satisfied with three:
Show Solution
Hans Theo Kuner [Kartothek A-K page 194] |
Of Hans Theo Kuner (or Theo Kuner) many problems could be quoted. May the reader be satisfied with three:
Show Solution
1.Kb6! (2.Sxc4+ Kd5 3.Sc7#)
1...Qd4 2.Sxd4 (3.Sc6#)Focal theme. Cycle of double refutations.
1...Qc3 2.Sd8 (3.Sc6#) 2.Sg5?/Sf8?
1...Qa2 2.Sg5 (3.Re4#) 2.Sd8?/Sf8?
1...Qc1 2.Sf8 (3.Sd7#) 2.Sg5?/Sd8?
Monday, January 23, 2012
January 24th
Eeltje Visserman (24-01-1922 – 23-03-1978) Dutch composer, Grandmaster and International Judge
E. Visserman was a wonderful composer who deservedly won numerous composing tourneys. He composed problems of all types, but mostly two- and threemovers. He was also the editor of a column in magazines "Tijdschrift van de KNSB" and "Probleemblad".
An anthology of his problems was published after his death: "Schaakproblemen van E. Visserman" by Albertus Marinus Koldijk, 1986.
Show Solution
Eeltje Visserman [maxeuwe.nl] |
E. Visserman was a wonderful composer who deservedly won numerous composing tourneys. He composed problems of all types, but mostly two- and threemovers. He was also the editor of a column in magazines "Tijdschrift van de KNSB" and "Probleemblad".
An anthology of his problems was published after his death: "Schaakproblemen van E. Visserman" by Albertus Marinus Koldijk, 1986.
Show Solution
1.Qh4 ! (2.Sh3+ Kf3 3.Qg3#)
1...Bxd3 2.Bc7 (3.e6#) (2.Bd8? 2.Sa4?)
1...cxd3 2.Bd8 (3.Qg3#) 2...f6 3.Se6# (not 2.Bc7? 2.Sa4?)
1...exd3 2.Sa4 (3.Be3#) (2.Bc7? 2.Bd8?)
1...Qxd3+ 2.Sxd3+ Bxd3/cxd3/exd3 3.Be3#
Triple avoidance.
1...Bxd3 2.Bc7 (3.e6#) (2.Bd8? 2.Sa4?)
1...cxd3 2.Bd8 (3.Qg3#) 2...f6 3.Se6# (not 2.Bc7? 2.Sa4?)
1...exd3 2.Sa4 (3.Be3#) (2.Bc7? 2.Bd8?)
1...Qxd3+ 2.Sxd3+ Bxd3/cxd3/exd3 3.Be3#
Triple avoidance.
Sunday, January 22, 2012
January 23rd
Victor Cioană (23-01-1939 - 07.01.2010) Romanian composer and player
Victor Cioană was the best solver in his hometown Suceava. Victor won several times the solving tourney organized by Romanian magazine "Revista Română de Şah”. It was only natural for him to publish his first problem in this same magazine. It was a helpmate in 4 with 2 solutions.
Show Solution
Victor (on the left) analyzing an endgame with Dieter Klosterman |
Victor Cioană was the best solver in his hometown Suceava. Victor won several times the solving tourney organized by Romanian magazine "Revista Română de Şah”. It was only natural for him to publish his first problem in this same magazine. It was a helpmate in 4 with 2 solutions.
Show Solution
Saturday, January 21, 2012
January 22nd
Jacob Bettmann (22-01-1865 - 22-04-1935) American composer
Jacob was the cousin of composer Henry Ward Bettmann.
Show Solution
FindAGrave |
Jacob was the cousin of composer Henry Ward Bettmann.
Show Solution
1.fxe4! zz
Other variations:
1...exd4 2.exd5#(An interesting realization of the Zilahi theme for a pair of pawns, with reciprocal captures between pawns)
1...dxe4 2.dxe5#
Other variations:
1...gxf2/g2 2.Qh3#
1...Kxd3 2.Rf3#
Friday, January 20, 2012
January 21st
Theodor Nissl (21-01-1878 - 16-02-1972) German composer
He was also a chess player: the reader may discover his game against Siegbert Tarrasch (Munich 1933).
Show Solution
Show Solution
Theodor Nissl was an advocate of the chess composing school known under the name of "Neudeutscher Schule". He composed his first problems shortly before WWI and became friends with numerous chess composers through epistolary exchanges (J. Kohtz & C. Kockelkorn, F. Sackmann, etc).
He was also a chess player: the reader may discover his game against Siegbert Tarrasch (Munich 1933).
A short biography in German can be found on Wikipedia.de. Other information in German can be found in the article "Das Pfälzer Dreigestirn" written by Dr. Hermann Weissauer about three composers from the Palatinate region - P.A.Orlimont, Franz Sackmann and Theodor Nissl.
The Nissl theme is nowadays better known under the name of Phoenix theme.Show Solution
1.Be6 ! (2.Bxd7 ~ 3.Se4+ Kb7 4.Sxc5+ Ka8 5.Bxc6#; or 3.Sf7+ or 3.Bc8 ~ 4.Bxa6 ~ 5.Sb5#)
1...dxe6 2.Sf5 (3.Sxg7 ~ 4.Sxe6#)
2...exf5 3.Bh2 3.f4 4.exf4 Kxd6 5.f5#
A difficult 5-mover with creation of an unexpected B-P battery.
1...dxe6 2.Sf5 (3.Sxg7 ~ 4.Sxe6#)
2...exf5 3.Bh2 3.f4 4.exf4 Kxd6 5.f5#
A difficult 5-mover with creation of an unexpected B-P battery.
Show Solution
1.Sa2! (2.Ra7+ Sxa7 3.b7#)
1...Rxa2 2.Rg2! Ra3 3.Ra2! Rxa2 4.Qg2! (threatening 5.Rb8# or 5.Qxa2+)
4...Rxg2 5.Ra7+ Sxa7 6.b7#
This problem featuring spectacular consecutive sacrifices is always a crowd-pleaser.
1...Rxa2 2.Rg2! Ra3 3.Ra2! Rxa2 4.Qg2! (threatening 5.Rb8# or 5.Qxa2+)
4...Rxg2 5.Ra7+ Sxa7 6.b7#
This problem featuring spectacular consecutive sacrifices is always a crowd-pleaser.
Thursday, January 19, 2012
January 20th
Harald Schmid (20-01-1932) Austrian composer
Show Solution
Show Solution
a) 1.Ba6 a4 2.Bb5 axb5 3.Sa6 bxa6 4.Qd7 a7 5.0-0-0 a8=Q#Excelsior, echo mates, castle.
b) 1.Qg5 h4 2.Be7 hxg5 3.Sf6+ gxf6 4.0-0 fxe7 5.Kh8 exf8=Q#
Wednesday, January 18, 2012
Tuesday, January 17, 2012
January 18th
Jean de Villeneuve-Esclapon (18-01-1860 - 24-11-1943) French composer
Biographical details can be found on this French site, where the photograph comes from, or on the new French chess problem site Problemiste here and here.
His best know endgame study is the 1st prize in Schweizerische Schachzeitung 1923, but the following draw study is also stimulating for the solver:
Show Solution
Jean de Villeneuve-Esclapon [Heritage Echecs] |
Biographical details can be found on this French site, where the photograph comes from, or on the new French chess problem site Problemiste here and here.
His best know endgame study is the 1st prize in Schweizerische Schachzeitung 1923, but the following draw study is also stimulating for the solver:
Show Solution
1. b6+! Kxb6 2. Sc8+! Sxc8 3. Ke6 b2 4. g7 b1=Q 5. g8=Q Qb3+ 6. Kd7 Qxg8 =
A delicious endgame with a beautiful ideal stalemate.
A delicious endgame with a beautiful ideal stalemate.
Monday, January 16, 2012
January 17th
The menu is especially rich today: do not miss the problems by the last composer in this entry.
[Addendum 25th January: by the last two composers!]
Karel Peter Traxler (17-01-1866 - 15-05-1936) Czech composer and player... and Catholic priest
Let's quote ChessGames.com:
Karel Traxler "is famous for the Traxler Counterattack (also known as the Wilkes-Barre Variation) in the Two Knights (C57) : 1.e4 e5 2.Nf3 Nc6 3.Bc4 Nf6 4.Ng5 Bc5. This line was introduced in the famous game J. Reinisch vs Traxler, 1890."
Show Solution
[Addendum 25th January: by the last two composers!]
Karel Peter Traxler (17-01-1866 - 15-05-1936) Czech composer and player... and Catholic priest
Karel Traxler [Wikipedia] |
Let's quote ChessGames.com:
Karel Traxler "is famous for the Traxler Counterattack (also known as the Wilkes-Barre Variation) in the Two Knights (C57) : 1.e4 e5 2.Nf3 Nc6 3.Bc4 Nf6 4.Ng5 Bc5. This line was introduced in the famous game J. Reinisch vs Traxler, 1890."
Show Solution
1.Sf4 ! (2.Qe6+ Kd4 3.Qf6+ Ke3 4.Qe5#)
1...Bd8 2.Qxc5+ Kf6 3.Qd4+ Ke7 4.Sg6#A typical example of the Bohemian chess problem school.
1...Sg8/Sf7 2.Qc5+ Kf6 3.Se8+ Kf7 4.Bg6# (3...Rxe8 4.Sh5#)
1...Re8 2.Sxe8 (3.Qe4#) 2...Kxf5 3.Qe6+ Kxf4 4.e3#
1...Rf8 2.Sf7+! and 2...Kxf5 3.Qe6+ Kxf4 4.Qe5/4.e3# or 2...Kf6 3.Qe6+ Kg7 4.Qg6# or 2...Sxf7 3.Qxc5+ Kf6/Kxf4 4.Sh5/e3# or 2...Rxf7 3.Qxc5+ Kf6/Kxf4 4.Sh5/e3#
Sunday, January 15, 2012
January 16th
Ilham Aliev (16-01-1967) Azerbaijani composer
Ilham Aliev is a successful endgame composer. One of his latest successes was 2nd special prize in the 2nd FIDE World Cup 2011.
Ilham Aliev is a successful endgame composer. One of his latest successes was 2nd special prize in the 2nd FIDE World Cup 2011.
Show Solution 1.Rd7+ {1.Kg1 Rxg5+ 2.Kf1 Ra5 3.Kg1 Rg5+} 1...Kc2 2.Rc7+ Kb2 (Kd2) 3.Rc1 {3.Rxb7+ Kc2 4.Rc7+ Kb2 5.Kg1 Rxg5+ 6.Kf1 Rd5 7.Ke1 Re5+ 8.Kf1 Rd5 9.Rb7+ Kc2 10.Kg1 Rg5+ 11.Kh2 Rh5+ 12.Kg1 Rg5+ 13.Kf1 Rd5 positional draw} 3...Kxc1 4.axb7 {4.a7 Kc2} 4...Ra1 5.Be5 {5.Kg1 Kc2+ 6.Kh2 Rb1} 5...Rb1 6.b8=R! +- {6.b8=Q?? Kd2+ 7.Qxb1 stalemate} |
Saturday, January 14, 2012
January 15th
Max A.K.S. Karstedt (15-01-1868 - 22-03-1945) German composer
Karstedt was also the discoverer of the K+B+S vs K+Q fortress (wKh1, Bg2, Se4) which is mentioned, for instance, in the June 2006 issue of BESN and is explained in details on Roberto Stelling's website.
Tom Morrell claimed to have discovered another K+B+S vs K+Q fortress (wKf2, Bf3, Sg2) but this claim is not sustained by the Nalimov database.
A charming endgame study by Karstedt was recently posted on ChicagoChess blog.
Karstedt was also the discoverer of the K+B+S vs K+Q fortress (wKh1, Bg2, Se4) which is mentioned, for instance, in the June 2006 issue of BESN and is explained in details on Roberto Stelling's website.
Tom Morrell claimed to have discovered another K+B+S vs K+Q fortress (wKf2, Bf3, Sg2) but this claim is not sustained by the Nalimov database.
A charming endgame study by Karstedt was recently posted on ChicagoChess blog.
Show Solution 1.Sd5 ! (2.Qe7 + Kf5/Kd5 3.Bc2/Qd6#) 1...Sd2+ 2.Kg4! (3.Qe7/Qxg8/Sf4#)2...Sf6+ 3.Qxf6#A spectacular key and pin mate. |
January 14th
Henry Wald Bettmann (14-01-1868 - 05-12-1935) American composer
Show Solution 1.a8=B! with the apparent threat 2.Bxf2/Rxf2 ZZ Rxa6# 1...fxg1=S/fxg1=B/fxg1=R/fxg1=Q 2.f8=S/f8=B/f8=R/f8=Q! ZZ 2... S/B/R/Q moves 3. S/B/R/Q is captured ZZ and 3...Rxa6# Historically, the first clean achievement of the Babson Task. |
Thursday, January 12, 2012
January 13th
Uri Avner (13-01-1941 - 10-06-2014) Israeli composer, Grandmaster and former President of the WFCC
Uri Avner [© Nikola Stolev] | Show Solution 1.Qc8 ! (2.Qxc5+ Kxc5 3.Rc8+ Kd4 4.Sc6+ Kc5 5.Scb4+ Kd4 6.Sc2+ Rxc2#) 1...Sf6 2.Be5+ Kxe5 3.Rxg5+ Kd4 4.Sf5+ Ke5 5.Sxg3+ Kd4 6.Se2+ Rxe2#Fireworks of White batteries and especially Siers batteries. |
Labels:
Avner,
Fischli,
Fjellström,
Garoufalidis,
Heydon,
january,
Mussuri,
Paoli
Wednesday, January 11, 2012
January 12th
Arnoldo Ellerman (12-01-1893 - 21-11-1969) Argentinian composer and International Master
Arnoldo Ellerman (Chess Pie 1922) [Chess History] |
Show Solution 1...g3 2.Qxf3#1.Qc6! (2.Sg7#) 1...dxc6/d6 2.Be6# Indirect unpin, Pelle move, changed mates. |
Tuesday, January 10, 2012
January 11th
Friedrich Hariuc (11-01-1937) Romanian composer living in Germany
Show Solution
Show Solution
1. Qf8 Sd4+ 2. Ke3 Kc3 3. Qf2 Sd5#Chameleon echo mates
1. Qh5 d4 2. Ke4 Sd5 3. Qf3 Sd6#
January 10th
Espen Backe (10-01-1963) Norwegian composer
Show Solution
Show Solution
a) 1.Qb2 Ba8 2.Qb7 Rg2+ 3.Kf3 Bxb7#Diagonal-orthogonal correspondence, critical moves.
b) 1.Qb7 Rh8 2.Qh7 Bf3+ 3.Kh3 Rxh7#
Labels:
Backe,
january,
Katsnelson,
Rinck,
Shulman
Monday, January 9, 2012
January 9th
Baruch Lender (09-01-1913 - 25-02-1994) Israeli composer
Biographical information about Baruch Lender can be found in "Lender combination: Baruch Lender and His Chess Problems" written by a trio of Israeli composers: Uri Avner, Paz Einat and Yoel Aloni and also on this webpage dedicated to Baruch Lender, the Lender combination and the book itself.
Show Solution
The Lender combination is a sort of mix of Salazar and (pseudo) le Grand:
Biographical information about Baruch Lender can be found in "Lender combination: Baruch Lender and His Chess Problems" written by a trio of Israeli composers: Uri Avner, Paz Einat and Yoel Aloni and also on this webpage dedicated to Baruch Lender, the Lender combination and the book itself.
Show Solution
Set play:
1...Bxd4[a] 2.Qxa6#[B]1.d5[D]? (2.Ne3#[A])
1...cxd4 2.Qc6#
1...Bc3 2.Ne3#[A]
1...Bd4[a] 2.Qxa6#[B]1.Rg4[C]! (2.Qxa6#[B])
1...Rc3/Bxa3[b] 2.Rg4#[C]
but 1...Re2!
1...Bxd4[a] 2.Ne3#[A]
1...Bxa3[b] 2.d5#[D]
1...Be6 2.Qxe6#
1...cxd4 2.Qc6#
The Lender combination is a sort of mix of Salazar and (pseudo) le Grand:
1. A? [2.B]
1...a(b) 2.C(D)#
1.C! [2.D]
1...a(b) 2.A(B)#
The curious reader may refer to the book "Lender combination: Baruch Lender and His Chess Problems" by Uri Avner, Paz Einat and Yoel Aloni.
Saturday, January 7, 2012
January 8th
Franz Pachl (08-01-1951) German composer and Grand Master
Show Solution
Show Solution
a) 1.Qf4 Rg1 2.Kg4 Se3#Anticipatory self-pin, triple-pin mates, model mates.
b) 1.Qd5 Ra6 2.Ke6 Sd4#
January 7th
Dinu Ioan Nicula (07-01-1968) Romanian solver, composer, arbiter and editor
Show Solution
Show Solution
1.Qe2 Sf3 2.Re7 Qd3 3.Qe5+ Sxe5#Pelle moves by the wQ, Black battery play, indirect unpin.
1.Qg4 Se2 2.Ra4 Kc5 3.Qb4+ Bxb4#
Friday, January 6, 2012
January 6th
Paul Răican (06-01-1957) Romanian composer and editor of French-speaking magazine Quartz.
Show Solution
Răican, Paul
Mat Plus, 2007 (27/781)
Special Prize
Mat Plus, 2007 (27/781)
Special Prize
#7 | Maximummer KoeKo PWC (Circé échange) b) wKd4-->b5 s#7 | 2 + 2 |
Show Solution
a) 1.dxe8=R [+bRd7] ! Z
1...Rg7 2.Ke5+ Rd7 3.Re7+ Kxe7 [+wRf6] 4.Rf8 Rd4 5.Kf6+ Kxf8 [+wRe7] 6.Re8 Rd8 7.Kg7#
b) 1.Kc6 ! Z
1...Re5 2.Kc7 Re8 3.dxe8=Q [+bRd7] Rg7 4.Qe5+ Rd7 5.Kc8 Rd4 6.Qb8 Rd8+ 7.Kxd8 [+bRc8] Ke7#
1...Rg7 2.Ke5+ Rd7 3.Re7+ Kxe7 [+wRf6] 4.Rf8 Rd4 5.Kf6+ Kxf8 [+wRe7] 6.Re8 Rd8 7.Kg7#
b) 1.Kc6 ! Z
1...Re5 2.Kc7 Re8 3.dxe8=Q [+bRd7] Rg7 4.Qe5+ Rd7 5.Kc8 Rd4 6.Qb8 Rd8+ 7.Kxd8 [+bRc8] Ke7#
Thursday, January 5, 2012
January 5th
Artur Mandler (05-01-1891 - 20-10-1971) Czech composer and Grandmaster
Show Solution
Show Solution
1.Kg6!
{Tries:1...Ka6 2.Kg7! Ka7 3.Kg8! Ka8
1.c5? dxc5 2.e5 c4 3.e6 c3 and the wP does not promote with check;
1.Kg5? Kb7 2.Kg6 (2.Kf5 Kc7) 2...Kc6 3.Kf7 (3.Kf6 Kb6) 3...Kb7 4.Kg8 (4.Ke7 Kc7; 4.Kf8 Kb8; 4.Ke8 Kc8) 4...Kc8 5.c5 Kc7 (5...Kd7 6.Kf7 dxc5 7.e5 c4 8.e6+) 6.Kf7 dxc5 7.e5 c4 and the wP still does not promote with check.}
{The bK is now on the 8th rank, everything is ready}4.c5 dxc5 5.e5 c4 6.e6 c3 7.e7 c2 8.e8=Q+ +-
Subscribe to:
Posts (Atom)