September 24th

Ladislav Cimburek (24-09-1867 - 27-02-1915) Czech composer

Ladislav Cimburek was a Bohemian composer.
Ilja Mikan selected 108 of his problems in an issue of "Galerie československých skladatelů" (Gallery of Czech composers) which can be downloaded here.

Cimburek, Ladislav
Prachskij Kongress, 1891
1^st Prize

#4

6 + 7

Show Solution

1.Qh4-g3 ! (2.Bf4xd6 [3.Qg3-f4/Qg3xd3#] 2...Ke4xf5 3.Qg3-f4+ Kf5-g6 4.Bc4-f7#)

1...Ke4-d4 2.Qg3xd3+ Kd4-c5 3.Bf4xd6+ Kc5-c6 4.Bc4-b5#
1...Ke4xf5 2.Qg3-g5+ Kf5-e4 3.Bc4-d5+ Ke4-d4 4.Bf4-e3#
1...Sf8-g6 2.Qg3-e3+ Ke4xf5 3.Bc4-e6+ Kf5-f6 4.Bf4-g5#

Three chameleon echo mates.

Cimburek, Ladislav
Zlatá Praha, 22^nd Apr 1887

#4

4 + 8

Show Solution

1.Qb1-h1 ! (2.Qh1xh4+ Kg5-f5 3.Ra4-e4 [4.Qh4-f4/Qh4-g4#] 3...g6-g5 4.Qh4-h7#)
1...Kg5-h6 2.Ra4xh4+
           2...Kh6-g7 3.Rh4-h8 [4.Qh1-h7/Qh1-h6#] 3...f6-f5 4.Qh1-a1#
           2...Kh6-g5 3.Qh1-e4 (4.Qe4-g4/Qe4-f4#) 3...f6-f5 4.Qe4-e7# {or dual 3.f2-f4+ Kg5-f5 4.Qh1-d5#}

Three echo mates, marred by a dual in the 3rd variation. Adding a black pawn on c6 would allow getting rid of the dual 3.f2-f4+ and keeping only the echo mate with 3...f6-f5 4.Qe4-e7#. There would then be a side variation 1...Kg5-f5 2.Qh1-e4+ Kf5-g5 3.Qe4-f4+ Kg5-h5 4.Qf4xh4#.